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Embedded Systems And The Volatile Keyword

Geoffrey Hunter Author
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Many C/C++ software engineers could go their entire life without ever needing to use the volatile keyword. However in embedded systems, knowing how the volatile keyword works and how to use it is a vital skill.

The volatile keyword is a qualifier you apply to a variable, e.g. volatile uint8_t my_var;. It tells the compiler that the value stored at this address may change at any time, even if the compiler cannot see a code path that would cause it to change. This forces the compiler to perform a read/write from memory every time the variable is used in the code, rather than the compiler storing the variable locally in a register or optimizing the read/write out completely!

You can place the keyword volatile before or after the type when declaring a variable (const behaves the same way). The basic syntax for defining a volatile variable is:

volatile uint8_t my_var;
uint8_t volatile my_var; // Alternative method, exactly the same as the line above

In the embedded world, it is common to want to use pointers that point to volatile memory, i.e. a pointer to an 8-bit memory mapped register for controlling a UART. Pointers to volatile data are defined with:

volatile uint8_t * ptr_to_register;

volatile is used for:

  • Variables which are read/written to from interrupts and also accessed outside the interrupt. If you forgot the volatile the compiler cannot set the code path that calls the interrupt (because interrupts are called asynchronously) and thus may assume nothing else touches the variable and cache the value in a register (or optimize out the read/write completely).
  • Memory addresses which point to hardware registers in microcontrollers (memory mapped registers). These hardware registers are liable to be changed at any time by the hardware (e.g. a bit in a UART peripheral register which indicates when there are received bytes available for reading), so the compiler cannot assume it's only changed when the code writes to it.

Any time a variable may be changed outside the flow of control of a piece of code accessing it, the variable should be declared volatile.

What volatile should not be used for:

  • Guaranteeing thread safe access of a shared variable between two threads. volatile provides some, but not all of the guarantees required for thread safe access. Other threading objects such as memory barriers, mutexes e.t.c are required, but these also provide the guarantees that volatile does, so volatile is not needed in this use case.

The Use Of volatile With Buffers

It is also common to write incoming data to buffers (e.g. ring buffers) from interrupts in embedded firmware, and then read the data back out of the buffer outside of the interrupt in the main application routine (or flip the read/write for outgoing data). volatile can be used when declaring the array of bytes in the buffer.

For example, to declare a 100-byte buffer which contains volatile data:

volatile char buffer[100];

This forces the compiler to generate code in the main app routine that goes out and reads the values in the buffer. If you did not use volatile, the compiler may infer that because the interrupt function that writes to the buffer never gets called (remember: the compiler can't see the interrupt being called), so it never has to read the values from the buffer because it will always stay as the initialized values. This can result in you reading garbage data from your buffer!

Below is an example in C++ of a volatile buffer than is written to from an ISR (interrupt service routine) and read from a main application thread (outside of the interrupt). Because this is on a web-based system, I didn't have access to true interrupts, so I simulated one with a separate thread instead. If you remove the volatile keyword, you should get undefined behaviour. In the case when I ran it, I got the same output as when declared volatile, which I think is because I couldn't get the compiler to optimize out the read.

(run this code at

// To build and run code:
// g++ main.cpp -lpthread; ./a.out
#include <iostream>
#include <memory>
#include <thread>

// This buffer needs to be declared volatile as the ISR writes to
// it (ISR faked with a separate thread)
volatile char buffer[3];

void isr_fn() {
char data[] = "abc";
// Copy the chars, ignore the null
for (int i = 0; i < 3; i++) {
buffer[i] = data[i];

int main() {
std::thread t1(isr_fn);
t1.join(); // Wait for ISR to finish writing to buffer

// Now read from buffer
for (int i = 0; i < 3; i++) {
std::cout << buffer[i];
std::cout << "\n";

memcpy() And volatile

memcpy() cannot operate on volatile data. This can be an annoyance if you are trying to copy data to or from a buffer (array of bytes, i.e. char *) which is declared volatile. However, you can easily make your own version of memcpy() which does work with volatile. Below is a example of a memcpy() equivalent that works with a destination buffer that is volatile:

// Version of memcpy that works with a volatile destination buffer
void memcpy_to_volatile(volatile char * dest, char * src, uint32_t num_bytes) {
for (uint32_t i = 0; i < num_bytes; i++) {
dest[i] = src[i];

Casting Away volatile


Casting away volatile on a variable can cause undefined behaviour.

In C++, you can use const_cast to cast away volatile (confusingly, it's called const_cast, but it actually casts away both const and volatile).

C++ Member Functions Declared volatile

TODO: Add info here.